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alert / js / node_modules / source-map / lib / binary-search.js
@Réz István Réz István on 18 Nov 2021 4 KB first commit
/* -*- Mode: js; js-indent-level: 2; -*- */
/*
 * Copyright 2011 Mozilla Foundation and contributors
 * Licensed under the New BSD license. See LICENSE or:
 * http://opensource.org/licenses/BSD-3-Clause
 */

exports.GREATEST_LOWER_BOUND = 1;
exports.LEAST_UPPER_BOUND = 2;

/**
 * Recursive implementation of binary search.
 *
 * @param aLow Indices here and lower do not contain the needle.
 * @param aHigh Indices here and higher do not contain the needle.
 * @param aNeedle The element being searched for.
 * @param aHaystack The non-empty array being searched.
 * @param aCompare Function which takes two elements and returns -1, 0, or 1.
 * @param aBias Either 'binarySearch.GREATEST_LOWER_BOUND' or
 *     'binarySearch.LEAST_UPPER_BOUND'. Specifies whether to return the
 *     closest element that is smaller than or greater than the one we are
 *     searching for, respectively, if the exact element cannot be found.
 */
function recursiveSearch(aLow, aHigh, aNeedle, aHaystack, aCompare, aBias) {
  // This function terminates when one of the following is true:
  //
  //   1. We find the exact element we are looking for.
  //
  //   2. We did not find the exact element, but we can return the index of
  //      the next-closest element.
  //
  //   3. We did not find the exact element, and there is no next-closest
  //      element than the one we are searching for, so we return -1.
  var mid = Math.floor((aHigh - aLow) / 2) + aLow;
  var cmp = aCompare(aNeedle, aHaystack[mid], true);
  if (cmp === 0) {
    // Found the element we are looking for.
    return mid;
  }
  else if (cmp > 0) {
    // Our needle is greater than aHaystack[mid].
    if (aHigh - mid > 1) {
      // The element is in the upper half.
      return recursiveSearch(mid, aHigh, aNeedle, aHaystack, aCompare, aBias);
    }

    // The exact needle element was not found in this haystack. Determine if
    // we are in termination case (3) or (2) and return the appropriate thing.
    if (aBias == exports.LEAST_UPPER_BOUND) {
      return aHigh < aHaystack.length ? aHigh : -1;
    } else {
      return mid;
    }
  }
  else {
    // Our needle is less than aHaystack[mid].
    if (mid - aLow > 1) {
      // The element is in the lower half.
      return recursiveSearch(aLow, mid, aNeedle, aHaystack, aCompare, aBias);
    }

    // we are in termination case (3) or (2) and return the appropriate thing.
    if (aBias == exports.LEAST_UPPER_BOUND) {
      return mid;
    } else {
      return aLow < 0 ? -1 : aLow;
    }
  }
}

/**
 * This is an implementation of binary search which will always try and return
 * the index of the closest element if there is no exact hit. This is because
 * mappings between original and generated line/col pairs are single points,
 * and there is an implicit region between each of them, so a miss just means
 * that you aren't on the very start of a region.
 *
 * @param aNeedle The element you are looking for.
 * @param aHaystack The array that is being searched.
 * @param aCompare A function which takes the needle and an element in the
 *     array and returns -1, 0, or 1 depending on whether the needle is less
 *     than, equal to, or greater than the element, respectively.
 * @param aBias Either 'binarySearch.GREATEST_LOWER_BOUND' or
 *     'binarySearch.LEAST_UPPER_BOUND'. Specifies whether to return the
 *     closest element that is smaller than or greater than the one we are
 *     searching for, respectively, if the exact element cannot be found.
 *     Defaults to 'binarySearch.GREATEST_LOWER_BOUND'.
 */
exports.search = function search(aNeedle, aHaystack, aCompare, aBias) {
  if (aHaystack.length === 0) {
    return -1;
  }

  var index = recursiveSearch(-1, aHaystack.length, aNeedle, aHaystack,
                              aCompare, aBias || exports.GREATEST_LOWER_BOUND);
  if (index < 0) {
    return -1;
  }

  // We have found either the exact element, or the next-closest element than
  // the one we are searching for. However, there may be more than one such
  // element. Make sure we always return the smallest of these.
  while (index - 1 >= 0) {
    if (aCompare(aHaystack[index], aHaystack[index - 1], true) !== 0) {
      break;
    }
    --index;
  }

  return index;
};